+-

我想要实现以下目标:
如果在返回Json的方法中引发了异常,则返回new Json(new {success = false,error =“ unknown”});
但是如果方法返回View,则返回Redirect
public async Task Invoke(HttpContext ctx)
{
try
{
await next(ctx);
}
catch (Exception ex)
{
HandleException(ctx, ex);
}
}
private static void HandleException(HttpContext context, Exception ex)
{
// some logger
LoggerService.Log(ex);
context.Response.Redirect("/Error/ErrorPage");
}
如何确定请求发送到哪里?我的意思是如何获取发送请求的方法类型?
因为我想做类似typeof(targetMethod)的事情来确定它是否是例如JsonResult
最佳答案
听起来您正在尝试处理Action方法引发的异常.在这种情况下,ASP.NET Core具有内置的
IExceptionFilter,它适合于此:
A filter that runs after an action has thrown an Exception.
为了实现您的目标,请创建一个CustomExceptionFilter:
public class CustomExceptionFilter : IExceptionFilter
{
private ILogger<CustomExceptionFilter> _logger;
public CustomExceptionFilter(ILogger<CustomExceptionFilter> logger)
{
this._logger = logger;
}
public void OnException(ExceptionContext context)
{
var ex = context.Exception;
var c = (ControllerActionDescriptor) context.ActionDescriptor;
if(c == null){
context.Result = new StatusCodeResult(500);
} else if (typeof(JsonResult) == c.MethodInfo.ReturnType) {
context.Result = new JsonResult(new { success = false, error = "unknown" });
} else {
// Redirect
this._logger.LogCritical(ex,ex.Message);
context.Result = new RedirectResult("/Error/ErrorPage");
}
}
}
并按如下所示注册此过滤器:
services.AddMvc(opts => {
opts.Filters.Add(typeof(CustomExceptionFilter));
});
这对我来说可以.
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转载注明原文:c#-异常处理:如果控制器方法返回json,则返回json,如果View,则返回Redirect - 乐贴网