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c#-异常处理:如果控制器方法返回json,则返回json,如果View,则返回Redirect
我想要实现以下目标:

如果在返回Json的方法中引发了异常,则返回new Json(new {success = false,error =“ unknown”});

但是如果方法返回View,则返回Redirect

public async Task Invoke(HttpContext ctx)
{
    try
    {
        await next(ctx);
    }
    catch (Exception ex)
    {
        HandleException(ctx, ex);
    }
}

private static void HandleException(HttpContext context, Exception ex)
{
    // some logger
    LoggerService.Log(ex);

    context.Response.Redirect("/Error/ErrorPage");
}

如何确定请求发送到哪里?我的意思是如何获取发送请求的方法类型?

因为我想做类似typeof(targetMethod)的事情来确定它是否是例如JsonResult

最佳答案
听起来您正在尝试处理Action方法引发的异常.在这种情况下,ASP.NET Core具有内置的 IExceptionFilter,它适合于此:

A filter that runs after an action has thrown an Exception.

为了实现您的目标,请创建一个CustomExceptionFilter:

public class CustomExceptionFilter : IExceptionFilter
{
    private ILogger<CustomExceptionFilter> _logger;

    public CustomExceptionFilter(ILogger<CustomExceptionFilter> logger)
    {
        this._logger = logger;
    }

    public void OnException(ExceptionContext context)
    {
        var ex = context.Exception;
        var c = (ControllerActionDescriptor) context.ActionDescriptor;

        if(c == null){
            context.Result = new StatusCodeResult(500);
        } else if (typeof(JsonResult) == c.MethodInfo.ReturnType) {
            context.Result = new JsonResult(new { success = false, error = "unknown" });
        } else {
            // Redirect
            this._logger.LogCritical(ex,ex.Message);
            context.Result = new RedirectResult("/Error/ErrorPage");
        }
    }
}

并按如下所示注册此过滤器:

services.AddMvc(opts => {
    opts.Filters.Add(typeof(CustomExceptionFilter));
});

这对我来说可以.

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